[RegCNET] error while running regcm.x
rajeshj at cusat.ac.in
rajeshj at cusat.ac.in
Thu Dec 31 08:27:39 CET 2009
Dear RegCM3 users,
While running RegCM3 in a linux cluster I get the following error message
. the domain has iy=90, ix=144 and kz=23. the model was run for two months
from 1jan1999 to 1mar1999. I could successfuly run the model for the same
period with iy=90 and ix=136.Is there any limit for iy*ix*t? What shall i
do to get rid off this error message as my aim is to run the model for one
year.
OUT-history written date = 1999012112.00000
BCs are ready from 1999012112 to 1999012118
at day = 20.5712, ktau = 11850 : 1st, 2nd time deriv of ps =
0.113 32E-04 0.58502E-07, no. of points w/convection = 1201
at day = 20.6580, ktau = 11900 : 1st, 2nd time deriv of ps =
0.213 12E-04 0.15721E-06, no. of points w/convection = 1156
at day = 20.7448, ktau = 11950 : 1st, 2nd time deriv of ps =
0.385 87E-04 0.36229E-06, no. of points w/convection = 1189
*** solar declination angle = -19.70 degrees.
dectim = 120960.000000000
OUT-history written date = 1999012118.00000
BCs are ready from 1999012118 to 1999012200
at day = 20.8316, ktau = 12000 : 1st, 2nd time deriv of ps =
0.808 75E-04 0.78657E-06, no. of points w/convection = 1269
at day = 20.9184, ktau = 12050 : 1st, 2nd time deriv of ps =
0.194 31E-03 0.22117E-05, no. of points w/convection = 1250
*** solar declination angle = -19.64 degrees.
dectim = 122400.000000000
OUT-history written date = 1999012200.00000
BCs are ready from 1999012200 to 1999012206
at day = 21.0052, ktau = 12100 : 1st, 2nd time deriv of ps =
0.844 00E-03 0.11727E-04, no. of points w/convection = 1182
at day = 21.0920, ktau = 12150 : 1st, 2nd time deriv of ps =
NaN NaN , no. of points w/convection = 0
at day = 21.1788, ktau = 12200 : 1st, 2nd time deriv of ps =
NaN NaN , no. of points w/convection = 0
*** solar declination angle = -19.58 degrees.
dectim = 123840.000000000
OUT-history written date = 1999012206.00000
BCs are ready from 1999012206 to 1999012212
at day = 21.2656, ktau = 12250 : 1st, 2nd time deriv of ps =
NaN NaN , no. of points w/convection = 0
at day = 21.3524, ktau = 12300 : 1st, 2nd time deriv of ps =
NaN NaN , no. of points w/convection = 0
at day = 21.4392, ktau = 12350 : 1st, 2nd time deriv of ps =
NaN NaN , no. of points w/convection = 0
*** solar declination angle = -19.53 degrees.
dectim = 125280.000000000
Thank you,
Rajesh J.
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